Difference between revisions of "Testing Area"
| Line 17: | Line 17: | ||
Let's try something really really complicated - Fourier transform of time-dependent Schrodinger: | Let's try something really really complicated - Fourier transform of time-dependent Schrodinger: | ||
| − | <html><img src="http://www.forkosh.dreamhost.com/mathtex.cgi?\huge i\hbar {\partial \psi(p) \over \partial t} = {p^2\over 2m} \psi(p) + V(i\hbar{\partial\over \partial x}) \psi(p)" title="i\hbar {\partial \psi(p) \over \partial t} = {p^2\over 2m} \psi(p) + V(i\hbar{\partial\over \partial x}) \psi(p)" alt="i\hbar {\partial \psi(p) \over \partial t} = {p^2\over 2m} \psi(p) + V(i\hbar{\partial\over \partial x}) \psi(p)" style="vertical-align:-2pt;" /></html> | + | <html><img src="http://www.forkosh.dreamhost.com/mathtex.cgi?\png \huge i\hbar {\partial \psi(p) \over \partial t} = {p^2\over 2m} \psi(p) + V(i\hbar{\partial\over \partial x}) \psi(p)" title="i\hbar {\partial \psi(p) \over \partial t} = {p^2\over 2m} \psi(p) + V(i\hbar{\partial\over \partial x}) \psi(p)" alt="i\hbar {\partial \psi(p) \over \partial t} = {p^2\over 2m} \psi(p) + V(i\hbar{\partial\over \partial x}) \psi(p)" style="vertical-align:-2pt;" /></html> |
Crikey. | Crikey. | ||
Revision as of 13:15, 2 July 2008
OK, let's try equations again.
Utter hack and terribly insecure:
<html><img src="http://www.forkosh.dreamhost.com/mathtex.cgi?alby=awesome" /></html>
Holy crap it worked.
<html><img src="http://www.forkosh.dreamhost.com/mathtex.cgi?\huge x^2+x^3"</html>
<html><img src="http://www.forkosh.dreamhost.com/mathtex.cgi?\rho=m/v"</html>
<html><img src="http://www.forkosh.dreamhost.com/mathtex.cgi?\rho= {m \over v}"</html>
Link to LaTeX MathML biznezz: http://www.andy-roberts.net/misc/latex/latextutorial9.html
Let's try something really really complicated - Fourier transform of time-dependent Schrodinger:
<html><img src="http://www.forkosh.dreamhost.com/mathtex.cgi?\png \huge i\hbar {\partial \psi(p) \over \partial t} = {p^2\over 2m} \psi(p) + V(i\hbar{\partial\over \partial x}) \psi(p)" title="i\hbar {\partial \psi(p) \over \partial t} = {p^2\over 2m} \psi(p) + V(i\hbar{\partial\over \partial x}) \psi(p)" alt="i\hbar {\partial \psi(p) \over \partial t} = {p^2\over 2m} \psi(p) + V(i\hbar{\partial\over \partial x}) \psi(p)" style="vertical-align:-2pt;" /></html>
Crikey.
